If `18,a,b,-3` are in AP, then `a+b=`

State 'T' for true and 'F' for false . I. A sequence is an A.P ., if and only if the sum of its n terms is of the form An^(2) +Bn , where A and B are constants . II. If 18, a, b , -3 are in A.P., then a+b = 15 . III If a,c,b are in A.P., then 2c=a+b . IV .The n^(th) term from the end of an A.P. is the (m-n+1)^(th) term from the beginning , where m terms are in A.P.

If 18, a, (b-3) are in AP, then find the value of (2a-b).

If a,b,c are in A.P. then

If 18 ,\ a ,\ b ,\ -3 are in A.P., the a+b= (a) 19 (b) 7 (c) 11 (d) 15

If a,b,c are in AP , then prove that : b+c,c+a,a+b are also in AP

If a,b,c are in A.P ,then 3^(a),3^(b),3^(c) shall be in (A) A.P (B) G.P (C) H.P (D) None of these

If a, b, c are in A.P., then show that (i) b + c – a, c + a – b, a + b – c are in A.P.

If a,b,c are in A.P., then a^(3)+c^(3)-8b^(3) is equal to

If a,b,c are in AP, than show that a^(2)(b+c)+b^(2)(c+a)+c^(2)(a+b)=(2)/(9)(a+b+c)^(3) .