If cos (A+B) =0 and sin (A-B) = `(sqrt(3))/(2)` then calculate the value of A.

If sin (3A-B) = 1 and cos (2A - B) = (sqrt(3))/(2) , then the value of sin A and cos B are .

If cos(A+B)=0andsin(A-B)=(sqrt(3))/(2) then find the value of tan(A-3B) .

If sin(A+B)=1 and cos(A-B)=(sqrt(3))/(2) then find A and B

If sin (A + B )=1 and cos(A -B)= frac(sqrt3)(2) , where A gt B.Find the value of B ?

If cos(A+B) = 0 and sin(A-B) = 1/2, then the value of B is: (Given 0^@ यदि cos(A+B) = 0 और sin(A-B) = 1/2, B का मान है:

Given that sin A=(sqrt(3))/(2) and cos B=0 then find the value of B-A

If sin(A+B)=(sqrt(3))/(2),cos(A-B)=(sqrt(3))/(2) and 0 then the value of A and B are :

If cos(A-B)=(1)/(2) and sin(A+B)=(sqrt(3))/(2) , then find A and B The following are the steps involved in solving the following problem. Arrange them in sequential order. (A) 2A=120^(@)implies A=60^(@) (B) :. A=60^(@),B=0^(@) . (C ) cos(A-B)=(1)/(2) implies cos(A-B) = cos60^(@) and sin(A+B)=(sqrt(3))/(2)implies sin(A+B) = sin 60^(@) . (D) A+B=60^(@) and A-B=60^(@) .