D,E,F are midpoints of sides BC,CA,AB of `DeltaABC`. Find the ratio of areas of `DeltaDEF` and `DeltaABC`.

Find the area of DeltaABC.

D(2,1,0) ,E(2,0,0),F(0,1,0) are midpoints of the sides BC,CA,AB of DeltaABC respectively . The , the centroid of DeltaABc is

P, Q, R are the midpoints of AB, BC, CA of DeltaABC and the area of DeltaABC is 20. The area of DeltaPQR is

If (2, 1), (-1, -2), (3, 3) are midpoints of sides BC, CA, AB of DeltaABC , then the equation of AB is

If D, E, F are the midpoints of BC, CA, AB of Delta ABC, then vec(A)D + vec(B)E + vec(C)F =

Assertion (A) : The radius of the circle inscribed in the triangle obtained by joining the middle points of the sides of DeltaABC is equal to half the radius of incircle of DeltaABC Reasons (R): In DeltaABC D, E, F be midpoints of the sides of DeltaABC, Delta 2s s denote area and perimeter of DeltaDEF then Delta=Delta//4= and s=s//2

If (1, 2), (4, 3), (6, 4) are the midpoints of the sides bar(BC), bar(CA), bar(AB) of DeltaABC , then the equation of AB is

D,E and F are the mid points of the sides BC, CA and AB respectivley of f triangle ABC then the ratio of the areas of triangle DEF and ABC =………..