Check and discuss the below relations in the case of angles between 0° and 90° , whether they hold for these angles or not? `tan (90- A) = cot A

Check and discuss the below relations in the case of angles between 0° and 90° , whether they hold for these angles or not? cot (90- A) = tan A

Check and discuss the below relations in the case of angles between 0° and 90° , whether they hold for these angles or not? cos (90^@- A) = sin A

Check and discuss the above relations in the case of angles between 0° and 90° , whether they hold for these angles or not? Sec (90^@- A) = cosec A

Check and discuss the above relations in the case of angles between 0° and 90° , whether they hold for these angles or not? cosec (90^@- A) = sec A

Check and discuss the above relations in the case of angles between 0^@ and 90^@ , whether they hold for these angles or not? Sin (90^@- A) = cos A

Check and discuss the above relations in the case of angle between 0^(@) and 90 ^(@) whether they hold for these angles or not?

Check and discuss the above relations [sin (90^@ - x) = (AB) /(AC) = cos x cos (90^@ - x) = (BC)/(AC) = sin x tan (90^@ - x) = (AB)/(BC) = cot x cot(90^@ - x) = (BC)/(AB) = tan x , cosec(90^@ - x) = (AC)/(AB) = sec x , sec(90^@ - x) = (AC)/(BC) = cosec x] , in the case of angle between 0^@ and 90^@ , whether they hold for these angles or not ?So, sin(90^@ - A) = cosA

Check and discuss the above relations [sin (90^@ - x) = (AB) /(AC) = cos x cos (90^@ - x) = (BC)/(AC) = sin x tan (90^@ - x) = (AB)/(BC) = cot x cot(90^@ - x) = (BC)/(AB) = tan x , cosec(90^@ - x) = (AC)/(AB) = sec x , sec(90^@ - x) = (AC)/(BC) = cosec x] , in the case of angle between 0^@ and 90^@ , whether they hold for these angles or not ?So, cos(90^@ - A) = sinA

Express: tan 65^@ + cot 49^@ in terms of angles between 0^@ and 45^@

Draw the pairs of angles as adjacent angles. Check whether they form linear pair.