A ball is thrown vertically upwards from the top of a building of height 29.4m and with an initial velocity 24.5 m/sec. If the height H of the ball from the ground level is given by `H = 29.4 + 24.5t - 4.9t^(2)`, then find the time taken by the ball to reach the ground.

A ball is thrown vertically upward from the top of a building 96feet tall with an initial velocity of 80feet per second. The distance S (in feet )of the ball from the ground, after t seconds is S = 96 + 80t − 16t^(2) . After how many seconds does the ball strike the ground.

From the top of a cliff of height 19.6m a ball is projected horizontally. Find the time taken by the ball to reach the ground (g =9.8 ms^(-2)) .

A ball is dropped from the top of a tower of height 78.4 m Another ball is thrown down with a certain velocity 2 sec later. If both the balls reach the ground simultaneously, the velocity of the second ball is

A ball is thrown vertically upwards with a velocity of 20ms^-1 from the top of a multistorey building. The height of the point from where the ball is thrown is 25.0 m from the ground. How high will the ball rise?