O is the centre of a centre having diameter AB. P is any point on the circle. Draw a perpendicular from P to AB, which meets AB at N. Prove that `PB^2 =AB.BN`

AB is a diameter of a circle. C is any point on the circle, angleACB=

AB is a diameter of a circle and 'C' is any point on the circumference of the circle .Then

AB is a diameter of a circle with centre at O. C is any point on the circle. If angleBOC = 110^@ , then angleBAC =

AB is diametr of the circle with centre at O and P is any point on the circle. If angle AOP=120^(@) then anglePBO =

N is the foot of the perpendicular form P to the diameter AB of the circle APB. P lies on the circle APB. Prove that PB^2=AB.NB ,

AB is a diameter of a circle with centre O and AC is a chord . The straight line through O parallel to AC meets the arc BC at D. Prove that, BD= CD.

AB is a diameter of a circle with centre O , P is any point on the circle, the tangent drawn through the point P intersects the two tangents drawn through the points A and B at the points Q and R respectively. If the radius of the circle be r , then prove that PQ.PR=r^(2) .

O is the centre of a circle and AB a diameter ABCD is acyclic quadrilateral. angleDAC = 40^@ , the the measure of angleBCD is ____

In the figure, O is the centre of the circle and AB = CD. OM is perpendicular on bar(AB) and bar(ON) is perpendicular on bar(CD) . Then prove that OM = ON.

PQ is a diameter of a circle and AB is such a chord of it that it is perpendicular to PQ . If C be the point of intersection of PQ and AB , then prove that PC.QC=AC.BC .