Write True or False :
Present price of a material is Rs. 100. Price of material decreased by 10% in every year. The price of it after 2 years is Rs.81.

Present price of a machine is Rs 2P and if price of the machine decrease by 2r% in each year, the price of machine after 2n years will be.

Write True or False: Present price of a comodity is Rs 100. Decreasing rate of the price of comodity is 10% per annum. Total decrease in two years is Rs 20.

The present value of a car is Rs 400000. If the value of the car decreases by 10% per annum, then find the value of the car after 3 years.

The present value of a machine be Rs. 2P and every year the value of it decreases by 2r% . Then the value of the machine after 2n years is

A. Write true of false: a. If Principal =Rs.p , rate of compound interest per annum =r% and time =n years, then the amount after 2 years is Rs. p(1+r/100)^(2) b. If principal =Rs. p and rate of compound interest per annum for first, 2nd and 3rd year be r_(1)%, r_(2)% and r_(3)% respectively, then total amount for 3 years. =Rs. p(1+(r_(1))/100)^(3)+Rs. p(1+(r_(2))/100)^(3)+Rs. p(1+(r_(3))/100)^(3)

Write True or False At present the population of a city is P and rate of increae of population p.a. is 100r% . Increase of population after n years will be P{(1+r)^n-1}.

The present price of a machine is ₹ 2V. If the price of the machine depriciates at a rate oa 2r% per annum, then the pricen of the machine after 2t year will be

The price of machine decreased by 10% in each year. If the present price of machine is Rs 1000 then calculate the price of a machine after 2 years.

The present value of a house in Rs. 100000. If the value of the house decreases by 10% per annum, then what will be the value of the house after 3 years.

Price of a machine is Rs 2,00,000. The price of it decrease in 1st year and 2nd year by 15% and 10% respectively. The price of the machine will be after 2 years is