Find K, for which the two planes x+ky+5z+2=0 and 3x-2y+kz-1=0 are perpendicular to one another.

Find k, for which the two planes x+ky+5z+2=0 and 3x-2y+kz-1=0 are prependicular to one another.

The value of m for which the planes 2x + 3y -z = 5 and 3x - my + 3z =6 are perpendicular to each other is

The value of m for which the planes 2x+3y-z=5 and 3x-my+3z=6 are perpendicular to each other is

If the lines x+(a-1)y+1=0 and 2x+a^2y-1=0 are perpendicular, then find the value of adot

If the straight lines kx – 5y + 4 = 0 and 4x – 2y + 5 = 0 are perpendicular to each other. Find the value of k.

The equation of the plane through the line of intersection of the planes 2x+y-z+5=0 and x+2y+3z=4 and perpendicular to the plane 5x+3y+6z=10 is -

Let P=0 be the equation of a plane passing through the line of intersection of the planes 2x-y=0a n d3z-y=0 and perpendicular to the plane 4x+5y-3z=8. Then the points which lie on the plane P=0 is/are a. (0,9,17) b. (1//7,21//9) c. (1,3,-4) d. (1//2,1,1//3)

Find the value of K for which the two equations x-ky=k and x+(k-2)y=2 will not be solved

Find the angle between the planes 2x+y-2z+3=0a n d 6x−2y+3z=5