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For a virtual are erect image magnificat...

For a virtual are erect image magnification is

A

negative

B

positive

C

A and B

D

none

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Magnification m =

What is 'magnification'?

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  • An object is placed infront of a concave mirror of focal length f. A virtual image is formed with a magnification of 2. To obtain a real image of same magnification, the object has to moved by a distance

    A
    f
    B
    `f//2`
    C
    `3f//2`
    D
    `2f//2`

  • A compound microscope has an objective of focal length 4 mm and an eye-piece of focal length 25 mm. The objective produces a real image at a distance of 180 mm. If the eye-piece is in normal adjustment the magnification is

    A
    45
    B
    90
    C
    225
    D
    440

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    A card sheet divided into squares each of size "1 mm"^(2) is being viewed at a distance of 9 cm through a magnifying glass (a converging lens of focal length 9 cm) held close to the eye. a) What is the magnification in produced by the lens? How much is the area of each square in the virtual image ?

    What should be the distance between the object in Exercise 30 and the magnifying glass if the virtual image of each square in the figure is to have an area of "6.25 mm"^(2) . Would you be able to see the squares distinctly with your eyes very close to the magnifier ? [Note : Exercises 29 to 31 will help you clearly understand the difference between magnification in absolute size and the angular magnification (or magnifying power) of an instrument.'

    In a compound microscope, the object is 1 cm from the objective lens. The lenses are 30 cm apart and the intermediate image is 5 cm from the eye-piece. What magnification is produced?

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