`Al_(s) + Fe_2O_3(s) rarr Al_2O_3(s) + Fe_(s)` (atomic masses of Al = 27 U Fe = 56 U and O = 16 U).Suppose that you are asked to calculate the amount of aluminium, required to get 1120 kg of iron by the above equation.

Al_((s)) + fe_(2)O_(3(s)) to Al_(2) O_(3(s)) + Fe_((s)) (atomic masses of Al = 27U, Fe = 56U, and O = 16U) 2Al_((s)) +Fe_(2)O_(3(s)) to Al_(2)O_(3(s)) + 2Fe_((s)) , is a balanced equation. (2 xx 27)U + (2xx 56 + 3xx 16)U to (2xx 27 + 3 xx 16) U + (2 xx 56) U {:(54U+160U,,to102U+112U),(or2" mol" + "1 mol",,to 1"mol" + 2"mol"),(54g + 160g ,, to 102 g + 112 g):} Suppose that your asked to calculate the amount of aluminium, required to get 1120 kg of iron by the above reaction.

Molecular mass of HNO_3 (Atomic masses of H=1U, N=14U, O=16U)-

Na_(2)CO_(3) + Fe_(2)O_(3) rarr A + CO_(2) What is A tn the reaction?

Al_((s))+Fe_(2)O_(3(s))rarrAl_(2)O_(3(s))+Fe_((s)) 54_((g))+160_(g)rarr 102g+112 was given, Then, the amount of aluminium required to get 1120 grams of iron is

Fe_(2)O_(3)+2AlrarrAl_(2)O_(3)+2Fe The above reaction is an example of :

In the formation of Al_(2)O_(3) from Al and O_(2) , if 1.5 mole of oxygen is used up, the mass of aluminium that reacted is

Extraction of aluminium from aluminium oxide (Al_(2)//O_(3)) is het done by

Fe_(2)O_(3(s))+2Al_((s))rarr 2Fe_((s))+Al_(2)O_(3(s)) is a/an …………….

Fe_(2)O_(3)+2Al rarr Al_(2)O_(3)+2Fe Name the compound which is oxidized in the above reaction.