The quantum numbers of electrons are given below. Arrange them in order of increasing energies . Do any of these combinations have same energy ?
a) `n=4,l=2,m_(l)=-2,m_(s)=+1//2`
b) `n=3,l=2,m_(l)=-1,m_(s)=-1//2`
c)`n=4,l=1,m_(l)=0,m_(s)=+1//2`
d) `n=3,l=1,m_(l)=-1,m_(s)=-1//2`

The quantum numbers of six electrons are given below. Arrange them in order of increasing energies. Do any of these combination have same energy. {:(1.,n=4,l=2,m_(l) = -2,m_(s)=-1//2,),(2.,n=3,l=2,m_(l) = 1,m_(s) = +1//2,),(3.,n=4,l=1,m_(l) = 0,m_(s) = +1//2,),(4.,n=3, l=2,m_(l) = -2,m_(s) = -1//2,),(5.,n=3,l=1,m_(l) = -1,m_(s) = +1//2,),(6.,n=4,l=1,m_(l) = 0,m_(s) = +1//2,):}

The quantum numbers n , l , m , m_s respectively of the electron 3d^1 are

Explain giving reasons , which of the following sets of quantum numbers are not possible . a) n=0,l=0,m_(l)=0,m_(s)=+(1)/(2) b) n=1,l=0,m_(l)=0,m_(s)=-(1)/(2) c) n=1,l=1,m_(l)=0,m_(s)=+(1)/(2) d) n=2,l=1,m_(l)=0,m_(s)=+(1)/(2) e) n=3,l=3,m_(l)=-3,m_(s)=+(1)/(2) f) n=3,l=1,m_(l)=0,m_(s)=+(1)/(2)

The maximum number of electrons that can have the set of quantum numbers, n=4, m_(l)=0 and m_(s)=1/2 is