In `DeltaABC`, equation of side BC is x+y-6=0, also the circumcentre and orhtocentre are (3, 1) and (2, 2) respectively, then the equation of the circumcircle of `DeltaABC` is

In triangle ABC ,the equation of side BC is x-y=0. The circumcenter and orthocentre of triangle are (2,3) and (5,8), respectively. The equation of the circumcirle of the triangle is x^(2)+y^(2)-4x+6y-27=0x^(2)+y^(2)-4x-6y-27=0x^(2)+y^(2)+4x+6y-27=0x^(2)+y^(2)+4x+6y-27=0

Let the circumcentre of DeltaABC is S (-1,0) and the midpoints of sides AB and AC are E(1,-2) and F(-2,1) respectively , then the equation of the circumcircle of DeltaABC us

If the coordinates of orthocentre O' are centroid G of a DeltaABC are (0,1) and (2,3) respectively, then the coordinates of the circumcentre are

Mid-points of the sides AB and AC of a DeltaABC are (3, 5) and (-3, -3) respectively, then the length of the side BC is

In Delta ABC equation of the right bisectors of the sides Ab and AC are x+y = 0 and x - y = 0 respectively .If A = (5,7) then equation of side BC is