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For the reaction Cl2 + 2I^(-) rarr I2 ...

For the reaction `Cl_2 + 2I^(-) rarr I_2 +2 Cl^(-)`, the initial concentration of I was `0.20 mol L^(-1)` and the conc. After 20 min. way `0.18 mol L^-1`. Then the rate of formation of `I_2` in `mol L^(-1)` would be

A

`1 xx 10^(-4)`

B

`5 xx 10^(-4)`

C

`1 xx 10^(-3)`

D

`5 xx 10^(-3)`

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