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A red blood cell was kept in a solution ...

A red blood cell was kept in a solution for a few where it got burst. The solution taken was:

A

Hypotonic

B

Concentrated sugar solution.

C

Isotonic

D

Hypertonic.

Text Solution

AI Generated Solution

The correct Answer is:
To determine which solution caused the red blood cell to burst, we need to understand the concepts of osmosis and the types of solutions: hypotonic, hypertonic, and isotonic. ### Step-by-Step Solution: 1. **Understanding Osmosis**: Osmosis is the movement of water across a semipermeable membrane from an area of lower solute concentration to an area of higher solute concentration. This process continues until equilibrium is reached. 2. **Types of Solutions**: - **Hypotonic Solution**: A solution that has a lower concentration of solute compared to the inside of the cell. This means it has a higher concentration of water. - **Isotonic Solution**: A solution that has the same concentration of solute as the inside of the cell. There is no net movement of water. - **Hypertonic Solution**: A solution that has a higher concentration of solute compared to the inside of the cell. This means it has a lower concentration of water. 3. **Effect of Hypotonic Solution on Red Blood Cells**: - When a red blood cell is placed in a hypotonic solution, water moves into the cell by osmosis because the concentration of solute is lower outside the cell. - As water enters the cell, the cell swells due to the influx of water. 4. **Outcome of Swelling**: - If the influx of water continues, the red blood cell will eventually swell to the point where it cannot contain the excess water, leading to the cell bursting (lysis). 5. **Conclusion**: Since the red blood cell was kept in a solution where it burst, the solution must have been hypotonic. Therefore, the correct answer is: - **A. Hypotonic solution**.
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