If the OP any osmotic system is 35 atm and its turgor pressure 9 units . Find out water potential presents in the osmotic system.

Options

A. `-44` units
B. ` -26` unit
C. ` 26` unit
D. ` -3.88` unit

Answer

To find the water potential (Ψ) in the osmotic system, we can use the following formula:

\[ \Psi = OP - TP \]

Where:
- Ψ = Water potential
- OP = Osmotic pressure
- TP = Turgor pressure

Given:
- OP = 35 atm
- TP = 9 units

Now, we can substitute the values into the formula:

1. **Substitute the values into the formula:**
\[ \Psi = 35 \, \text{atm} - 9 \, \text{units} \]

2. **Perform the subtraction:**
\[ \Psi = 26 \, \text{units} \]

3. **Consider the sign of water potential:**
Water potential is typically expressed as a negative value in biological systems, especially when referring to osmotic systems. Therefore, we express the result as:
\[ \Psi = -26 \, \text{units} \]

Thus, the water potential present in the osmotic system is **-26 units**.