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A population will not exist in Hardy-Wei...

A population will not exist in Hardy-Weinberg equilibrium if:

A

There is no migration

B

The population is large

C

Individuals mate selectively

D

There are no mutations

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### Step-by-Step Solution: 1. **Understanding Hardy-Weinberg Equilibrium**: - The Hardy-Weinberg equilibrium is a principle that describes a population that is not evolving. For a population to be in this state, certain conditions must be met, including no mutations, random mating, no natural selection, extremely large population size, and no gene flow (migration). 2. **Identifying Factors that Disrupt Equilibrium**: - Any factor that introduces changes to the allele frequencies in a population can disrupt the Hardy-Weinberg equilibrium. The main factors include: - **Mutations**: Changes in the DNA sequence can introduce new alleles into the population. - **Genetic Drift**: Random changes in allele frequencies, particularly in small populations. - **Migration (Gene Flow)**: Movement of individuals into or out of a population can alter allele frequencies. - **Natural Selection**: Differential survival and reproduction can lead to changes in allele frequencies. - **Non-random Mating**: If individuals preferentially mate based on certain traits, it can affect allele frequencies. 3. **Analyzing the Given Options**: - The question asks which condition would prevent a population from being in Hardy-Weinberg equilibrium. We need to evaluate the options based on the criteria established. - **Option 1: No migration** - This is a condition for Hardy-Weinberg equilibrium; thus, this option does not disrupt it. - **Option 2: Population is large** - A large population size helps maintain equilibrium; therefore, this option does not disrupt it. - **Option 3: Individuals mate selectively** - This introduces non-random mating, which can lead to changes in allele frequencies and disrupt equilibrium. - **Option 4: No mutation** - This is also a condition for maintaining Hardy-Weinberg equilibrium; thus, this option does not disrupt it. 4. **Conclusion**: - The correct answer is that a population will not exist in Hardy-Weinberg equilibrium if **individuals mate selectively** (Option 3).
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