If `a^2+b^2=1t h e n(1+b+i a)/(1+b-i a)=` `1` b. `2` c. `b+i a` d. `a+i b`

If a^2+b^2=1 t h e n (1+b+i a)/(1+b-i a)= 1 b. 2 c. b+i a d. a+i b

If A=[[a+i b, c+i d],[-c+i d, a-i b]] and a^2+b^2+c^2+d^2=1,t h e n ,A^(-1) is equal to a. [[a+i b,-c+i d],[c+i d, a-i b]] b. [[a-i b,-c-i d],[-c-i d, a+i b]] c. [[a+i b,-c-i d],[-c+i d, a-i b]] d. none of these

If z(1+a)=b+i ca n da^2+b^2+c^2=1, then [(1+i z)//(1-i z)= A. (a+i b)/(1+c) B. (b-i c)/(1+a) C. (a+i c)/(1+b) D. none of these

If x(t) is a solution of ((1+t)dy)/(dx)-t y=1 and y(0)=-1 then y(1) is (a) ( b ) (c)-( d )1/( e )2( f ) (g) (h) (i) (b) ( j ) (k) e+( l )1/( m )2( n ) (o) (p) (q) (c) ( d ) (e) e-( f )1/( g )2( h ) (i) (j) (k) (d) ( l ) (m) (n)1/( o )2( p ) (q) (r) (s)

If A=[[1,-1],[ 2, 1]],B=[[a,1],[b,-1]]a n d(A+B)^2=A^2+B^2+2A B ,t h e n a. a=-1 b. a=1 c. b=2 d. b=-2

Let x_1, x_2, ,x_n be x_n observations. Let y_i=a x_i+b for i=1,2,...,n where a and b are constants. If the mean of x_i's is 48 and their standard deviation is 12, the mean of y_i 's is 55 and standard deviation of y_i's is 15, the values of a and b are (a) a=1. 25 ,b=-5 (b) a=-1. 25 ,b=5 (c) a=2. 5 ,b=-5 (d) a=2. 5 ,b=5

Let x_1, x_2, ,x_n be x_n observations. Let y_i=a x_i+b for i=1,2,...,n where a and b are constants. If the mean of x_i's is 48 and their standard deviation is 12, the mean of y_i 's is 55 and standard deviation of y_i's is 15, the values of a and b are (a) a=1. 25 ,b=-5 (b) a=-1. 25 ,b=5 (c) a=2. 5 ,b=-5 (d) a=2. 5 ,b=5

If a=1+i , then a^2 equals A. 1-i B. 2i C. (1+i)(1-i) D. (i-1)

(1+2i+3i^2)/(1-2i+3i^2) equals a. i b. -1 c. -i d. 4

If z=(i)^(i)^(((i)))w h e r e i=sqrt(-1),t h e n|z| is equal to 1 b. e^(-pi//2) c. e^(-pi) d. none of these