The polar form of `(i^(25))^3` is `cospi/2+isinpi/2` b. `cospi+i\ s inpi` c. `cospi-isinpi` d. `cospi/2-\ i s in\ pi/2`

The polar form of (i^(25))^3 is a. cos(pi/2)+isin(pi/2) b. cospi+i\ sinpi c. cospi-isinpi d. cos(pi/2)-\ i sin(pi/2)

The polar form of the complex number (i^(25))^(3) is

The argument of (1-i)/(1+i) is a. -pi/2 b. pi/2 c. (3pi)/2 d. (5pi)/2

Column I, Column II (one of the values of z ) z^4-1=0 , p. z=cospi/8+isinpi/8 z^4+1=0 , q. z=cospi/8-isinpi/8 i z^4+1=0 , r. z=cospi/4isinpi/4 i z^4-1=0 , s. z=cos0+isin0

Write (i^(25))^3 in polar form.

Find the value of expression (cospi/2+i sin(pi/2))(cos(pi/(2^2))+i sin(pi/(2^2)))......oo

The amplitude of 1/i is equal to 0 b. pi/2 c. -pi/2 d. pi

cospi/5+cos(2pi)/5+cos(6pi)/5+cos(7pi)/5=0

If y="sec"(tan^(-1)x),t h e n(dy)/(dx)a tx=1 is (a) cospi/4 (b) sinpi/2 (c) sinpi/6 (d) cospi/3

If inside a big circle exactly n(nlt=3) small circles, each of radius r , can be drawn in such a way that each small circle touches the big circle and also touches both its adjacent small circles, then the radius of big circle is r(1+cos e cpi/n) (b) ((1+tanpi/n)/(cospi/pi)) r[1+cos e c(2pi)/n] (d) (r[s inpi/(2n)+cos(2pi)/n]^2)/(sinpi/n)