`int1/(1+sqrt(x))"dx"` is equal to `a. 2sqrt(x)+2ln|1+sqrt(x)|+c` b. `2sqrt(x)-2ln|1+sqrt(x)|+c` c. `2sqrt(x)-2ln|1-sqrt(x)|+c` d. `2sqrt(x)-ln|1+sqrt(x)|+c`

int1/(1+sqrt(x))"dx" is equal to 2sqrt(x)+2ln|1+sqrt(x)|+c b. 2sqrt(x)-2ln|1+sqrt(x)|+c c. 2sqrt(x)-2ln|1-sqrt(x)|+c d. 2sqrt(x)-ln|1+sqrt(x)|+c

log(sqrt(x)+1/sqrt(x))

int 1/ sqrt (a^2 + x^2) dx = log ( x + sqrt(x^2 + a^2)) + c

"tan"(cos^(-1)x) is equal to x/(1+x^2) b. (sqrt(1+x^2))/x c. (sqrt(1-x^2))/x d. sqrt(1-2x)

intsqrt(x/(1-x))\ dx is equal to (a) sin^(-1)sqrt(x)+C (b) sin^(-1){sqrt(x)-sqrt(x(1-x))}+C (c) sin^(-1){sqrt(x(1-x))}+C (d) sin^(-1)sqrt(x)-sqrt(x(1-x))+C

int ( 1+ x + sqrt( x+ x^(2)))/(( sqrt(x) + sqrt( 1+x))dx is equal to

int(dx)/((1+sqrt(x))sqrt((x-x^2))) is equal to (a) (1+sqrt(x))/((1-x)^2)+c (b) (1+sqrt(x))/((1+x)^2)+c (c) (1-sqrt(x))/((1-x)^2)+c (d) (2(sqrt(x)-1))/(sqrt((1-x)))+c

int (x^4-1)/(x^2)sqrt(x^4+x^2+1) dx equal to (A) sqrt((x^4+x^2+1)/x) + c (B) sqrt(x^4 + 2 - 1/x^2) + c (C) sqrt(x^2 + 1/x^2 + 1) + c (D) sqrt((x^4-x^2+1)/x) + c

If y=log{sqrt(x-1)-sqrt(x+1)} , show that (dy)/(dx)=(-1)/(2sqrt(x^2-1))

4int(sqrt(a^6+x^8))/x dx is equal to (a) sqrt(a^6+x^8)+(a^3)/2ln|(sqrt(a^6+x^8)+a^3)/(sqrt(a^6+x^8)-a^3)|+c (b) a^6ln|(sqrt(a^6+x^8)-a^3)/(sqrt(a^6+x^8)+a^3)|+c (c) sqrt(a^6+x^8)+(a^3)/2ln|(sqrt(a^6+x^8)-a^3)/(sqrt(a^6+x^8)+a^3)|+c (d) a^6ln|(sqrt(a^6+x^8)+a^3)/(sqrt(a^6+x^8)-a^3)|+c