The equation of a line `4x-4y-z+11=0=x+2y-z-1` can be put as `x/2=(y-2)/1=(z-3)/4` (b) `(x-2)/2=(y-2)/1=z/4` `(x-2)/2=y/1=(z-3)/4` (d) None of these

The equation of a line 4x-4y-z+11=0=x+2y-z-1 can be put as (a)x/2=(y-2)/1=(z-3)/4 (b) (x-2)/2=(y-2)/1=z/4 (c) (x-2)/2=y/1=(z-3)/4 (d) None of these

The lines (x-1)/1=(y-2)/2=(z-3)/(3) and (x-1)/1=y/3 =z/4 are

The equation of the line intersection of the planes 4x+4y-5z=12 and 8x+12y-13z=32 can be written as: (A) x/2=(y-1)/3=(z-2)/4 (B) x/2=y/3=(z-2)/4 (C) (x-1)/2=(y-2)/3=z/4 (D) (x-1)/2=(y-2)/(-3)=z/4

Which of the following line is passing through point of intersection of line (x-4)/(2)=(y-3)/(2)=(z-5)/(1) and the plane x+y+z=2 (a) (x)/(2)=(y+1)/(3)=(z-3)/(4) (b) (x-2)/(3)=(y-1)/(3)=(z-3)/(2) (c) (x)/(2)=(y+1)/(3)=(z-2)/(4) (d) (x-2)/(2)=(y+1)/(3)=(z+3)/(4)

The lines (x-2)/(1)=(y-3)/(1)=(z-4)/(-k) and (x-1)/(k)=(y-4)/(2)=(z-5)/(1) are coplanar, if

If the lines (x-2)/(1)=(y-3)/(1)=(z-4)/(lamda) and (x-1)/(lamda)=(y-4)/(2)=(z-5)/(1) intersect then

Equation of theine passing through hati+hatj-3hatk and perpendiculr to the plane 2x-4y+3z+5=0 is (A) (x-1)/2=(1-y)/(-4)=(z-3)/3 (B) (x-1)/2=(1-y)/4=(z+3)/3 (C) (x-2)/1=(y+4)/1)=(z-3)/3 (D) (x-1)/(-2)=(1-y)/(-4)=(z-3)/3

The line (x-2)/1=(y+4)/(2)=(z-3)/3 and x/2=(y-1)/(4)=(z+3)/(6) are

Find the equation of line through (-4, 1,3) & parallel to the plane x+y+z=3 while the line intersects another line whose eqution is x+y-z=x+2y-3z+5 (a) (x+4)/(-3)=(y-1)/(-2)=(z-3)/(1) (b) (x+4)/(1)=(y-1)/(2)=(z-3)/(-3) (c) (x+4)/(-3)=(y-1)/(2)=(z-3)/(1)

The equation of the plane which is equally inclined to the lines (x-1)/2=y/(-2)=(z+2)/(-1)a n d=(x+3)/8=(y-4)/1=z/(-4) and passing through the origin is/are a. 14 x-5y-7z=0 b. 2x+7y-z=0 c. 3x-4y-z=0 d. x+2y-5z=0