The equation of the circle whose diameter is the common chord of the circles; `x^2+y^2+3x+2y+1=0` and `x^2+y^2+3x+4y+2=0` is:

`x^2+y^2+8x+10 y+2=0`
`x^2+y^2-5x+4y+7=0`
`2x^2+2y^2+6x+2y+1=0`
None of these

Explanation

Here, S1 is `x^2+y^2+3x+2y+1=0`.

S2 is `x^2+y^2+3x+4y+2=0`

As both circles have common chord, we can have

`x^2+y^2+3x+2y+1 = x^2+y^2+3x+4y+2`
`=>y=-1/2->Eq(1)`

Now, equation of the required circle can be generate by:

`S1+lambdaS2 = 0` (From, family of circles equation)

`=>x^2+y^2+3x+2y+1+lambda(x^2+y^2+3x+4y+2) = 0`

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