The base BC of a triangle ABC is bisected at the point (p,q) and the equations to the sides AB and AC are `px +qy = 1` and `qx +py = 1`. The equation of the median through A is

The base BC of a triangle ABC is bisected at the point (a, b) and equation to the sides AB and AC are respectively ax+by=1 and bx+ay=1 Equation of the median through A is:

The base B C of a A B C is bisected at the point (p ,q) & the equation to the side A B&A C are p x+q y=1 & q x+p y=1 . The equation of the median through A is: (p-2q)x+(q-2p)y+1=0 (p+q)(x+y)-2=0 (2p q-1)(p x+q y-1)=(p^2+q^2-1)(q x+p y-1) none of these

D is the mid-point of side BC of a triangle ABC.AD is bisected at the point E and BE produced cuts AC at the point X. Prove that BE:EX=3:1.

The vertices of Delta PQR are P (2, 1) , Q (2, 3) and R (4, 5) . Find equation of the median through the vertex R.

In the figure, given, ABC is a triangle and BC is parallel to the y-axis. AB and AC intersect the y-axis at P and Q respectively. Find the equation of the line AC.

In an isosceles triangle ABC, the coordinates of the points B and C on the base BC are respectively (1, 2) and (2. 1). If the equation of the line AB is y= 2x, then the equation of the line AC is

The equation of the sides of a triangle are x+2y+1=0, 2x+y+2=0 and px+qy+1=0 and area of triangle is Delta .

In the given figure ABC is a triangle and BC is parallel to the Y-axis. AB and AC intersects the y-axis at Pand Q respectively. (iv) Find the equation of the line AC.

ABC is a triangle A line is drawn parallel to BC to meet AB and AC in D and E respectively. Prove that the median through A bisects DE.

Let G be the centroid of triangle ABC and the circumcircle of triangle AGC touches the side AB at A If AC = 1, then the length of the median of triangle ABC through the vertex A is equal to