The equation of the circle of radius 5 i...

The equation of the circle of radius 5 in the first quadrant which touches the x-axis and the line `3x-4y=0` is `x^2+y^2-24 x-y-25=0` `x^2+y^2-30 x-10 y+225=0` `x^2+y^2-16 x-18 y-64=0` `x^2+y^2-20 x-12 y+144=0`

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The equation of a circle with radius 5 and touching both the coordinate axes is x^2+y^2+-10 x+-10 y+5=0 x^2+y^2+-10 x+-10 y=0 x^2+y^2+-10 x+-10 y+25=0 x^2+y^2+-10 x+-10 y+51=0

The equation to the circle which touches the axis of y at the origin and passes through (3, 4) is 2(x^2+y^2)-3x=0 3(x^2+y^2)-25 x=0 4(x^2+y^2)-25y=0 4(x^2+y^2)-25 x+10=0

Find the equation of the circle concentric with the circle x^2 + y^2 - 4x - 6y - 3 = 0 and which touches the y axis

The equation of the parabola whose focus is (1,-1) and the directrix is x+y+7=0 is (a) x^2+y^2-2x y-18 x-10 y=0 (b) x^2+y^2-18 x-10 y-45=0 (c) x^2-18 x-10 y-45=0 (d) x^2+y^2-2x y-18 x-10 y-45=0

The equation of the circle having its centre on the line x+2y-3=0 and passing through the points of intersection of the circles x^2+y^2-2x-4y+1=0a n dx^2+y^2-4x-2y+4=0 is x^2+y^2-6x+7=0 x^2+y^2-3y+4=0 c. x^2+y^2-2x-2y+1=0 x^2+y^2+2x-4y+4=0

Find the equation of the radical axis of the following circles. x^2+y^2-2x-4y-1=0 x^2+y^2-4x-6y+5=0

Find the equation of the circle which touches the lines 4x-3y+10=0a n d4x-3y-30=0 and whose centre lies on the line 2x+y=0.

The equation of the circle passing through the point of intersection of the circles x^2+y^2-4x-2y=8 and x^2+y^2-2x-4y=8 and the point (-1,4) is x^2+y^2+4x+4y-8=0 x^2+y^2-3x+4y+8=0 x^2+y^2+x+y=0 x^2+y^2-3x-3y-8=0

The equation of the circle having the intercept on the line y+2x=0 by the circle x^2 + y^2 + 4x + 6y = 0 as a diameter is : (A) 5x^2 + 5y^2 - 8x + 16y =0 (B) 5x^2 + 5y^2 + 8x - 16y =0 (C) 5x^2 + 5y^2 - 8x - 16y =0 (D) 5x^2 + 5y^2 + 8x+- 16y =0

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