If `1 tan^(-1) x + sin^(-1).(2x)/(1 + x^(2))` is independent of x, then

If 2tan^(-1)x+sin^(-1)((2x)/(1+x^2) ) is independent of x then :

If 2tan^(-1)x+sin^(-1)(2x)/(1+x^2) is independent of x , then x >1 (b) x<-1 (c) 0

The complete set of values of x for which 2 tan^(-1)x+cos^(-1)((1-x^(2))/(1+x^(2))) is independent of x is :

Given that , tan^(-1) ((2x)/(1-x^(2))) = {{:(2 tan^(-1) x"," |x| le 1),(-pi +2 tan^(-1)x","x gt 1),(pi+2 tan^(-1)x"," x lt -1):} sin^(-1)((2x)/(1+x^(2))) ={{:(2 tan^(-1)x","|x|le1),(pi -2 tan^(-1)x","x gt 1 and ),(-(pi+2tan^(-1))","x lt -1):} sin^(-1) x + cos^(-1) x = pi//2 " for " - 1 le x le 1 sin^(-1) ((4x)/(x^(2)+4)) + 2 tan^(-1)( - x/2) is independent of x , then

If |x| le 1 , then 2tan^(-1)x + sin^(-1)((2x)/(1+x^(2))) is equal to

Solve tan^(-1) x + sin^(-1) x = tan^(-1) 2x

sin (tan ^(-1)2x)

If sin^(-1)((4x)/(x^2+4))+2tan^(-1)(-x/2) is independent of x , find the values of xdot

If x >1 , then 2\ tan^(-1)x+sin^(-1)((2x)/(1+x^2)) is equal to (a) 4tan^(-1)x (b) 0 (c) pi/2 (d) pi

If y = 2tan^(-1)x+sin^(-1)((2x)/(1+x^(2))) , then "………"lt y lt "………" .