Let `f(x) = max{|x^2 - 2 |x||,|x|}` and `g(x) = min{|x^2 - 2|x||, |x|} `then

If f(x)=max{x^(2)-4,|x-2|,|x-4|} then:

Let f(x) = max. {|x^2 - 2| x ||,| x |} then number of points where f(x) is non derivable, is :

Let f(x)=f_1(x)-2f_2 (x) , where ,where f_1(x)={((min{x^2,|x|},|x|le 1),(max{x^2,|x|},|x| le 1)) and f_2(x)={((min{x^2,|x|},|x| lt 1),({x^2,|x|},|x| le 1)) and let g(x)={ ((min{f(t):-3letlex,-3 le x le 0}),(max{f(t):0 le t le x,0 le x le 3})) for -3 le x le -1 the range of g(x) is

Let f (x) =x + sqrt(x^(2) +2x) and g (x) = sqrt(x^(2) +2x)-x, then:

Let f(x) = x^(2) + 2x +5 and g(x) = x^(3) - 1 be two real functions. Find (f+g)(x), (f-g)(x), (fg)(x) and ((f)/(g))(x) .

Let g(x) = f(f(x)) where f(x) = { 1 + x ; 0 <=x<=2} and f(x) = {3 - x; 2 < x <= 3} then the number of points of discontinuity of g(x) in [0,3] is :

Let f(x)={x+1,x >0, 2-x ,xlt=0 and g(x)={x+3,x 0)g(f(x)).

Let f(x) = ||x| -1| , g(x) = |x| + |x-2| , h (x) = max { 1,x,x^(3)} If a, b,c are the no .of points where f(x), g(x) and h(x) , are not differentiable then the value of a+ b + c is …..

Let f(x) = x^(3) - x^(2) + x + 1 and g(x) = {{:(max f(t)",", 0 le t le x,"for",0 le x le 1),(3-x",",1 lt x le 2,,):} Then, g(x) in [0, 2] is

Let f(x)=[x] and g(x)=|x| . Find (f+2g)(-1)