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The radius of the circle whose equation ...

The radius of the circle whose equation in parametric form is `P(theta)=(acostheta+bsintheta,asintheta-bcostheta),` is : `(a+b)/2` (b) `sqrt(a b)` `sqrt(a^2+b^2)` (d) `(a b)/(a+b)`

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If acosheta+bsintheta=4 & asintheta - bcostheta= 3 then a^2+b^2

If x=acostheta-bsinthetaandy=asintheta+bcostheta , then show that : x^(2)+y^(2)=a^(2)+b^(2)

If acostheta+bsintheta=m and asintheta-bcostheta=n , prove that a^2+b^2=m^2+n^2

If acostheta+bsintheta=m and asintheta-bcostheta=n , Prove that a^2+b^2=m^2+n^2

x=acostheta+bsintheta and y=asintheta-bcostheta, show that y^2(d^2y)/(dx^2)-x(dy)/(dx)+y=0

If acostheta+bsintheta=4 and asintheta-bcostheta=3 , then a^2+b^2 = (a) 7 (b) 12 (c) 25 (d) None of these

If acostheta+bsintheta=m and asintheta-bcostheta=n , then show that a^(2)+b^(2)=m^(2)+n^(2) .

If tantheta=a/b , then (asintheta+bcostheta)/(asintheta-bcostheta) is equal to (a) (a^2+b^2)/(a^2-b^2) (b) (a^2-b^2)/(a^2+b^2) (c) (a+b)/(a-b) (d) (a-b)/(a+b)

If acostheta+b sintheta=x and asintheta-bcostheta=y prove that a^2+b^2=x^2+y^2

If tantheta=a/b , show that (asintheta-bcostheta)/(asintheta+bcostheta)=(a^2-b^2)/(a^2+b^2)

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