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If `(x_1, y_1)&(x_2, y_2)` are the solutions of the equaltions, `(log)_(225)(x)+log_(64)(y)=4` and `(log)_x(225)-(log)_y(64)=1,` Then which of the following is/are correct.
a. `(log)_(225)x_1dot(log)_(225)x_2=4`
b. `(log)_(225)x_1+(log)_(225)x_2=6`
c. `|(log)_(64)y_1-(log)_(64)y_2|=2sqrt(5)`
d. `(log)_(30)(x_1x_2y_1y_2)=12`

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If (x_1, y_1)&(x_2, y_2) are the solutions of the equaltions, (log)_(225)(x)+log_(64)(y)=4a n d(log)_x(225)-(log)_y(64)=1, (A) (log)_(225)x_1dot(log)_(225)x_2=4 (B). (log)_(225)x_1+(log)_(225)x_2=6 (C). |(log)_(64)y_1-(log)_(64)y_2|=2sqrt(5) (D). (log)_(30)(x_1x_2y_1y_2)=12

If (x_1, y_1)&(x_2, y_2) are the solutions of the equaltions, (log)_(225)(x)+log_(64)(y)=4a n d(log)_x(225)-(log)_y(64)=1, (log)_(225)x_1dot(log)_(225)x_2=4 b. (log)_(225)x_1+(log)_(225)x_2=6 c. |(log)_(64)y_1-(log)_(64)y_2|=2sqrt(5) d. (log)_(30)(x_1x_2y_1y_2)=12

Comprehension (Q. No. 6 to Q. No. 8) Let (x_1, y_1)&(x_2, y_2) are the solutions of the equation, (log)_(225)(x)+(log)_(64)(y)=4 and (log)_x(225)-(log)_y(64)=1 (log)_(225)x_1dot(log)_(225)x_2= 2 (b) 4 (c) 6 (d) 8

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