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The incorrect statement is (a) p vec -q ...

The incorrect statement is (a) `p vec -q ` is logically equivalent to `~ pvvqdot` (b) If the truth-values of`p ,q, r` are `T , F , T` respectively, then the truth value of `(pvvq)^^(qvvr)` is `Tdot` (c) `~(pvvqvvr)-= ~p^^~ q^^ ~r` (d) The truth value of `p^^~(p^^q)` is always `Tdot`

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The incorrect statement is (A) p →q is logically equivalent to ~p ∨ q. (B) If the truth-values of p, q r are T, F, T respectively, then the truth value of (p ∨ q) ∧ (q ∨ r) is T. (C) ~(p ∨ q ∨ r) = ~p ∧ ~q ∧ ~r (D) The truth-value of p ~ (p ∧ q) is always T

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construct truth table for p ^^ (q vv r)

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