If `f(x)=(1-s in2x+cos2x)/(2cos2x)` , then the value of `f(16^0)dotf(29^0)` is `1/2` `1/4` `1` `3/4`

If f(x)=inte^(x)(tan^(-1)x+(2x)/((1+x^(2))^(2)))dx,f(0)=0 then the value of f(1) is

If f (x )= (x-1) ^(4) (x-2) ^(3) (x-3) ^(2) then the value of f '(1) +f''(2) +f''(3) is:

f(x)+f(1-1/x)=1+x for x in R-{0,1}. Find the value of 4f(2).

If f(x) = cos x cos 2x cos 4x cos 8x cos 16x then find f' (pi/4)

"If "f(x)=(x-1)^(4)(x-2)^(3)(x-3)^(2)(x-4), then the value of f'''(1)+f''(2)+f'(3)+f'(4) equals

If f(x) = cos x cos 2x cos 4x cos (8x). cos 16x then find f' (pi/4)

If f(x) = cos x cos 2x cos 4x cos (8x). cos 16x then find f' (pi/4)

If f(x)=cos^(- 1)x+cos^(- 1){x/2+1/2sqrt(3-3x^2)} then

Let f(x) = |{:(cos x ,1,0 ),(1,2cosx,1),(0,1,2cosx):}| then

Let f(x)=|(cos x,e^(x^2) , 2x cos^2x/2),(x^2, sec x, sinx+x^3),(1,2,x+tan x)| then the value of int_(-pi/2)^(pi/2)(x^2+1)(f(x)+f''(x))dx