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Which one of the following is not a contradiction? `[~ p^^(pvv~ q)]^^q` b. `(~ p^^q)^^p` c. `[(p (vec)q)(vec) p]^^~ p` d. `(~ q (vec) ~ p)harr(p (vec) q)`

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Which of the following is not equivalent to (p^^~ q)->r (a) ~(q v ~ p)->r (b) ~ r->(~ p v q) (c) ~((p^^(~ q))^^(~ r)) (d) ~ r->(~ p^^q)

(p^^~q)^^(~p^^q) is

(p^^~q)^^(~p^^q) is

The following statement (p to q) to [(~p to q) to q] is

((p^^q)vv(pvv~q))^^(~p^^~q)) is equivalent to (A) ~p^^~q (B) p^^~q (C) pvv~q (D) ~pvvq

Which of the following statement is not a fallacy? Option1 p ∧ ( ~ ( ~ p ⇒ q ) ) Option2 ~ ( ( p ∧ q ) ⇒ p ) Option3 ~ ( p ⇒ ( p ∨ q ) ) Option4 ~ p ∨ ( ~ p ⇒ q )

Which of the following is false? a. (p=>q)hArr(~ q=>~ p) is a contradiction b. pvv(~ p) is a tautology c. ~(~ p)hArr(~ q=>~ p) is a tautology d. p^^(~ p) is a contradiction

The Boolean Expression (p^^~ q)vvqvv(~ p^^q) is equivalent to : (1) ~ p^^q (2) p^^q (3) pvvq (4) pvv~ q

The logically equivalent proposition of phArrq is (p^^q)vv(p^^q) b. (p=>q)^^(p=>q) c. (p^^q)vv(p=>q) d. (p^^q)(pvvq)

The logically equivalent proposition of phArrq is a. (p^^q)vv(p^^q) b. (p=>q)^^(q=>p) c. (p^^q)vv(p=>q) d. (p^^q)(pvvq)

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