Let `L_1:3x+4y=1a n dL_2=5x-12 y+2=0` be two given lines. Let image of every point on `L_1` with respect to line `L` lies an `L_2` then possible equations of `L` can be (a) `14 x+112 y-23=0` (b) `64 x-8y-3=0` (c) `11 x-4y=0` (d) `52 y-45 x=7`

The equation of line l_(1) is y=2x+3 , and the equation of line l_(2) is y=2x-5.

The circle x^2+y^2-4x-2y=11 makes equal intercepts on the lines L_1: x+2y+1=0 and L_2dot Then equation of L_2 cannot be 2x+y+1=0 2x-y+3=0 2x+y=0 (d) 3x-2y+2=0

The equation of line l_(1) is y=(5)/(2)x-4 , and the equation of line l_(2) is y=-(2)/(5)x+9 .

Let the straight lines x+y-2=0, 2x-y+1=0 and px+qy-r=0 be concurrent and l_1 and l_2 be the two members of the family of lines 2px+2qy+4r=0 which are nearest and farthest from origin : Now answer the question : The eqation of line l_2 is : (A) 3x+15y-52=0 (B) 3x+15y+52=0 (C) 3x-15y+52=0 (D) 3x-15y-52=0

Let (2,3) be the focus of a parabola and x + y = 0 and x-y= 0 be its two tangents. Then equation of its directrix will be (a) 2x - 3y = 0 (b) 3x +4y = 0 (c) x +y = 5 (d) 12x -5y +1 = 0

The line L_1-=4x+3y-12=0 intersects the x-and y-axies at Aa n dB , respectively. A variable line perpendicular to L_1 intersects the x- and the y-axis at P and Q , respectively. Then the locus of the circumcenter of triangle A B Q is (a) 3x-4y+2=0 (b) 4x+3y+7=0 (c) 6x-8y+7=0 (d) none of these

The line L_1-=4x+3y-12=0 intersects the x-and y-axies at A and B , respectively. A variable line perpendicular to L_1 intersects the x- and the y-axis at P and Q , respectively. Then the locus of the circumcenter of triangle A B Q is (a) 3x-4y+2=0 (b) 4x+3y+7=0 (c) 6x-8y+7=0 (d) none of these

Given ABCD is a parallelogram with vertices as A(1,2),B(3,4) and C(2,3) . Then the equation of line AD is (A) x+y+1=0 (B) x-y+1=0 (C) -x+y+1=0 (D) x+y-1=0

A line 4x+y=1 passes through the point A(2,-7) and meets line BC at B whose equation is 3x -4y +1=0 , the equation of line AC such that AB=AC is (a) 52x +89y +519=0(b) 52x +89y-519=0 c) 82x +52y+519=0 (d) 89x +52y -519=0

A line 4x+y=1 passes through the point A(2,-7) and meets line BC at B whose equation is 3x -4y +1=0 , the equation of line AC such that AB=AC is (a) 52x +89y +519=0(b) 52x +89y-519=0 c) 82x +52y+519=0 (d) 89x +52y -519=0