Projection of line `(x+1)/2+(y+1)/(-1)=(z+3)/4` on the plane `x+2y+z=6;` has equation `x+2y+z-6=0=9x-2y-5z-8` b. `x+2y+z+6=0,9x-2y+5z=4` c. `(x-1)/4=(y-3)/(-7)=(z+1)/(10)` d. `(x+3)/4=(y-2)/7=(z-7)/(-10)`

Image of line (x - 2)/3 = (y - 1)/1 = (z - 1)/(-4) in the plane x + y + z = 7 is

The line (x-3)/1=(y-4)/2=(z-5)/2 cuts the plane x+y+z=17 at

Find the equation of the projection of the line (x-1)/2=(y+1)/(-1)=(z-3)/4 on the plane x+2y+z=9.

The line (x-2)/1=(y+4)/(2)=(z-3)/3 and x/2=(y-1)/(4)=(z+3)/(6) are

Which of the following line is passing through point of intersection of line (x-4)/(2)=(y-3)/(2)=(z-5)/(1) and the plane x+y+z=2 (a) (x)/(2)=(y+1)/(3)=(z-3)/(4) (b) (x-2)/(3)=(y-1)/(3)=(z-3)/(2) (c) (x)/(2)=(y+1)/(3)=(z-2)/(4) (d) (x-2)/(2)=(y+1)/(3)=(z+3)/(4)

Perpendiculars are drawn from points on the line (x+2)/2=(y+1)/(-1)=z/3 to the plane x + y + z=3 The feet of perpendiculars lie on the line (a) x/5=(y-1)/8=(z-2)/(-13) (b) x/2=(y-1)/3=(z-2)/(-5) (c) x/4=(y-1)/3=(z-2)/(-7) (d) x/2=(y-1)/(-7)=(z-2)/5

Find the equations of the projection of the line (x+1)/- 2=(y-1)/3=(z+2)/4 on the plane 2x+y+4z=1

A plane through the line (x-1)/1=(y+1)/(-2)=z/1 has the equation (A) x+y+z=0 (B) 3x+2y-z=1 (C) 4x+y-2z=3 (D) 3x+2y+z=0

Find the equation of line through (-4, 1,3) & parallel to the plane x+y+z=3 while the line intersects another line whose eqution is x+y-z=x+2y-3z+5 (a) (x+4)/(-3)=(y-1)/(-2)=(z-3)/(1) (b) (x+4)/(1)=(y-1)/(2)=(z-3)/(-3) (c) (x+4)/(-3)=(y-1)/(2)=(z-3)/(1)

The image of the line (x-1)/3=(y-3)/1=(z-4)/(-5) in the plane 2x-y+z+3=0 is the line (1) (x+3)/3=(y-5)/1=(z-2)/(-5) (2) (x+3)/(-3)=(y-5)/(-1)=(z+2)/5 (3) (x-3)/3=(y+5)/1=(z-2)/(-5) (3) (x-3)/(-3)=(y+5)/(-1)=(z-2)/5