Internal bisector of `angle A ` of `Delta ABC` meets side BC to D. A line drawn through D perpendicular to AD intersects the side AC at E and side AB at. F. If a,b,c represent sides of `Delta ABC,` then

Internal bisector of /_A of triangle ABC meets side BC at D. A line drawn through D perpendicular to AD intersects the side AC at E and the side AB at F. If a, b, c represent sides of DeltaABC , then

Internal bisector of /_A of triangle ABC meets side BC at D. A line drawn through D perpendicular to AD intersects the side AC at E and the side AB at F. If a, b, c represent sides of DeltaABC , then

Perpendicular bisectors of the sides AB and AC of a triangle ABC meet at O. What do you call the point ?

If D id the mid-point of the side BC of a triangle ABC and AD is perpendicular to AC , then

Perpendicular bisectors of the sides AB and AC of a triangle ABC meet at O. Does the perpendicular bisector of BC pass through O?

D,E and F are the middle points of the sides of the triangle ABC, then

Let the incircle of a Delta ABC touches sides BC, CA and AB at D,E and F, respectively. Let area of Delta ABC be Delta and thatof DEF be Delta' . If a, b and c are side of Detla ABC , then the value of abc(a+b+c)(Delta')/(Delta^(3)) is (a) 1 (b) 2 (c) 3 (d) 4

In Delta ABC, AB =AC and D is a piont in side BC such that AD bisect angle BAC. Show that AD is perpendicular bisector of side BC.

In a triangle ABC, AB = BC, AD is perpendicular to side BC and CE is perpendicular to side AB. Prove that : AD = CE.

DeltaABC is a right triangle right angled at A such that AB = AC and bisector of /_C intersects the side AB at D . Prove that AC + AD = BC .