A natural number is selected at random from the set `{1<=x <=100}`. The probability that number satisfies the inequation `x^2+15<=16x`, is :-

A three-digit number is selected at random from the set of all three-digit numbers. The probability that the number selected has all the three digits same is 1//9 b. 1//10 c. 1//50 d. 1//100

A natural number is chosen at random from the first 100 natural numbers. The probability that x+(100)/x > 50 is 1//10 b. 11//50 c. 11//20 d. none of these

A natural number is chosen at random from the first 100 natural numbers. The probability that x+(100)/x > 50 is 1//10 b. 11//50 c. 11//20 d. none of these

Two different numbers are selected at random from the set S={1, 2, 3, ……10}, then the probability that sum of selected numbers is divisible by 2 a/b, where a and b are co-prime then b is equal to ___.

Three different numbers are selected at random from the set A={1,2,3,……..,10} . Then the probability that the product of two numbers equal to the third number is (p)/(q) , where p and q are relatively prime positive integers then the value of (p+q) is :

Write the probability that a number selected at random from the set of first 100 natural numbers is a cube.

Write the probability that a number selected at random from the set of first 100 natural numbers is a cube.

Three natural numbers are taken at random from the set of first 100 natural numbers. The probability that their A.M. is 25, is

Three different numbers are selected at random from the set A = (1, 2, 3,...., 10). The probability that the product of two of the numbers is equal to the third is

Statement-1 : Three natural number are taken at random from the set A={x:1 lt x lt= 100, x in N} the probability that the A.M of the numbers taken is 25 is equal to (""^74C_2)/(""^100C_3) . Statement-2 : Let A = {2, 3, 4 …. 20}. A number is chosen at random from set A and it is bound to be a prime number. The probability that it is more than 10 is 1/5 . Statement-3 : The probability of three person having the same date month for the birthday is 1/((365)^2) .