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If the line 2x-2y+lambda=0 is a secant ...

If the line `2x-2y+lambda=0` is a secant to the parabola `x^2=-8y ,` then `lambda` lies in the interval `(4,oo)` (b) `(-oo,4)` (c) `(0,4)` (d) `Non eoft h e s e`

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