If complex number (3+2i s in x)/(1-2i s ...

If complex number `(3+2i s in x)/(1-2i s in x)` is purely imaginary then `x=` `npi+-pi/6` b. `n p+-pi/3` c.`2npi+-pi/3` d. `2npi+-pi/6`

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If complex number (3+2i sin x)/(1-2i sin x) is purely imaginary then x= npi+-pi/6 b. n p+-pi/3 c. 2npi+-pi/3 d. 2npi+-pi/6

If (3+2i sintheta)/(1-2i sintheta) is a real number and 0lt theta lt 2pi , then theta is a. pi \ b. pi/2 \ c. pi/3 \ d. pi/6

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Which of the following is true for z=(3+2isintheta)(1-2sintheta)w h e r ei=sqrt(-1) ? (a) z is purely real for theta=npi+-pi/3,n in Z (b)z is purely imaginary for theta=npi+-pi/2,n in Z (c) z is purely real for theta=npi,n in Z (d) none of these

The argument of the complex number (i/2-2/i) is equal to (a) pi/2 (b) pi/4 (c) pi/12 (d) (3pi)/4

If 4sin^2theta=1, then the values of theta are 2npi+-pi/3,\ n in Z b. npi+-pi/3,\ n in Z c. npi+-pi/6,\ n in Z d. 2npi+-pi/6,\ n in Z

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The general values of theta satisfying the equation 2sin^2theta-3sintheta-2=0 is (n in Z)dot npi+(-1)^npi/6 (b) npi+(-1)^npi/2 npi+(-1)^n(5pi)/6 (d) npi+(-1)^n(7pi)/6

The general solution of the equation 7cos^2theta+3sin^2theta=4 is theta=2npi+-pi/6,\ n Z b. theta=2npi+-(2pi)/3,\ n Z c. theta=2npi+-pi/3,\ n Z d. none of these

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