`(d^2x)/(dy^2)` equals: `((d^2y)/(dx^2))^(-1)` (b) `-((d^2y)/(dx^2))^(-1)((dy)/(dx))^(-3)` `((d^2y)/(dx^2))((dy)/(dx))^(-2)` (d) `-((d^2y)/(dx^2))((dy)/(dx))^(-3)`

(d^2x)/(dy^2) equals: (1) ((d^2y)/(dx^2))^-1 (2) -((d^2y)/(dx^2))^-1 ((dy)/(dx))^-3 (3) -((d^2y)/(dx^2))^-1 ((dy)/(dx))^-2 (4) -((d^2y)/(dx^2))^-1 ((dy)/(dx))^3

(d^2x)/(dy^2) equals: (1) ((d^2y)/(dx^2))^(-1) (2) -((d^2y)/(dx^2))^(-1)((dy)/(dx))^(-3) (3) ((d^2y)/(dx^2))^(-1)((dy)/(dx))^(-2) (4) -((d^2y)/(dx^2))^(-1)((dy)/(dx))^(-3)

(d^2x)/(dy^2) equals: (1.) ((d^2y)/(dx^2))^-1 (2) -((d^2y)/(dx^2)) ((dy)/(dx))^-3 (3) -((d^2y)/(dx^2))^-1 ((dy)/(dx))^-2 (4) -((d^2y)/(dx^2))^-1 ((dy)/(dx))^3

Solve (d^2y)/(dx^2)=((dy)/(dx))^2

Solve (d^2y)/(dx^2)=((dy)/(dx))^2

If x=logp and y=1/p ,then (a) (d^2y)/(dx^2)-2p=0 (b) (d^2y)/(dx^2)+y=0 (c) (d^2y)/(dx^2)+(dy)/(dx)=0 (d) (d^2y)/(dx^2)-(dy)/(dx)=0

If R=([1+((dy)/(dx))^2]^(3//2))/((d^2y)/(dx2)) , then R^(2//3) can be put in the form of a. 1/(((d^2y)/(dx^2))^(2//3))+1/(((d^2x)/(dy^2))^(2//3)) b. 1/(((d^2y)/(dx^2))^(2//3))-1/(((d^2x)/(dy^2))^(2//3)) c. 2/(((d^2y)/(dx^2))^(2//3))+2/(((d^2x)/(dy^2))^(2//3)) d. 1/(((d^2y)/(dx^2))^(2//3))1/(((d^2x)/(dy^2))^(2//3))

If y=xlog(x/(a+b x)),t h e nx^3(d^2y)/(dx^2)= (a) x(dy)/(dx)-y (b) (x(dy)/(dx)-y)^2 y(dy)/(dx)-x (d) (y(dy)/(dx)-x)^2

If R=([1+((dy)/(dx))^2]^(-3//2))/((d^2y)/(dx2)) , then R^(2//3) can be put in the form of 1/(((d^2y)/(dx^2))^(2//3))+1/(((d^2x)/(dy^2))^(2//3)) b. 1/(((d^2y)/(dx^2))^(2//3))-1/(((d^2x)/(dy^2))^(2//3)) c. 2/(((d^2y)/(dx^2))^(2//3))+2/(((d^2x)/(dy^2))^(2//3)) d. 1/(((d^2y)/(dx^2))^(2//3))dot1/(((d^2x)/(dy^2))^(2//3))

Which of the following differential equations has y = x as one of its particular solution? (A) (d^2y)/(dx^2)-x^2(dy)/(dx)+x y=x (B) (d^2y)/(dx^2)+x(dy)/(dx)+x y=x (C) (d^2y)/(dx^2)-x^2(dy)/(dx)+x y=0 (D) (d^2y)/(dx^2)+x(dy)/(dx)+x y=0