Area bounded by the curve `y=maxdot{(sin x ,cos x)} and x` -axis, between the lines `x=pi//4xa n dx=2pi` is equal to a.`((4sqrt(2)-1))/(sqrt(2))` sq. unit b. `(4sqrt(2)-1)` sq. unit c. `((4sqrt(2)-1))/2` sq. unit d. none of these

The area bounded by the curves y""=""cos""x""a n d""y""="sin""x between the cordinates x""=""0""a n d""x""=(3pi)/2 is (1) 4sqrt(2)-""2 (2) 4sqrt(2)""1 (3) 4sqrt(2)+""1 (4) 4sqrt(2)""2

The area bounded by the curve y=x^(2)(x-1)^(2) with the x - axis is k sq. units. Then the value of 60 k is equal to

The area bounded by the curves y=x(x-3)^2a n dy=x is________ (in sq. units)

The area bounded by the curves y=sqrt(x),2y+3=x , and x-axis in the 1st quadrant is (A) 18 sq. units (B) (27)/4 sq.units (C) 4/3 sq.units (D) 9 sq. units

Let f(x) be a non-negative continuous function such that the area bounded by the curve y=f(x), the x-axis, and the ordinates x=pi/4a n dx=beta>pi/4i sbetasinbeta+pi/4cosbeta+sqrt(2)betadot Then f(pi/2) is (pi/2-sqrt(2)-1) (b) (pi/4+sqrt(2)-1) -pi/2 (c) (1-pi/4+sqrt(2))

The area bounded by the curve y=log_ex , the x-axis and the line x=e is (A) e sq. units (B) 1 sq. unit (C) (1-1/e) sq. units (D) (1+1/e) sq. units

The area bounded by the curve y=log_ex , the x-axis and the line x=e is (A) e sq. units (B) 1 sq. unit (C) (1-1/e) sq. units (D) (1+1/e) sq. units

If the area bounded by the curves x^(2)+y le 2 and y ge x is (k)/(2) sq. units, then 2k is equal to

The area bounded by y=sec^-1 x,y=cosec^-1x, and line x-1=0 is (a) log(3+2sqrt2)-pi/2 sq. units (b) pi/2-log(3+2sqrt2) sq. units (c) pi-(log)_e 3 sq. units (d) non of these

lim_(x to 0) (sin^(2) x)/(sqrt(2)-sqrt(1+cos x))= (A) sqrt(2) (B) 2 (C) 4 (D) 4sqrt(2)