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If f(x)=x^αlogx and f(0)=0, then the val...

If `f(x)`=`x^αlogx` and `f(0)`=`0`, then the value of ′α′ for which Rolle's theorem can be applied in [0,1] is (A) -2 (B) -1 (C) 0 (D) `1/2`

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If f(x)={(x^(alpha)logx , x > 0),(0, x=0):} and Rolle's theorem is applicable to f(x) for x in [0, 1] then alpha may equal to (A) -2 (B) -1 (C) 0 (D) 1/2

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