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If tangent at point `(1, 2)` on curve `y = ax^(2) + bx + (7)/(2)` be parallel to normal at `(-2, 2)` on curve `y = (x^(2) + 6x + 10)` then

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The tangent to y = ax ^(2)+ bx + (7 )/(2) at (1,2) is parallel to the normal at the point (-2,2) on the curve y = x ^(2)+6x+10. Then the vlaue of a/2-b is:

The tangent to y=a x^2+b x+7/2a t(1,2) is parallel to the normal at the point (-2,2) on the curve y=x^2+6x+10 , then a=-1 b. a=1 c. b=5/2 d. b=-5/2

At what points on the curve y=x^2 on [-2,\ 2] is the tangent parallel to x-axis?

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