A spherical rain drop evaporates at a rate proportional to its surface area at any instant `tdot` The differential equation giving the rate of change of the radius of the rain drop is _____

If a spherical rain drop evaporates at a rate proportional to its surface area. Form a differential equation indicating the rate of change of the radius of the rain drop.

Assume that a rain drop evaporates at a rate proportional to its surface area. Form a differential equation involving the rate of change of the radius of the rain drop.

Spherical rain drop evaporates at a rate proportional to its surface area. The differential equation corresponding to the rate of change of the radius of the rain drop if the constant of proportionality is K >0 is

Spherical rain drop evaporates at a rate proportional to its surface area. The differential equation corresponding to the rate of change of the radius of the rain drop if the constant of proportionality is K >0 is (a) ( b ) (c) (d)(( e ) dy)/( f )(( g ) dt)( h ) (i)+K=0( j ) (k) (b) ( l ) (m) (n)(( o ) d r)/( p )(( q ) dt)( r ) (s)-K=0( t ) (u) (c) ( d ) (e) (f)(( g ) d r)/( h )(( i ) dt)( j ) (k)=K r (l) (m) (d) None of these

Assume that a spherical rain drop evaporates at a rate proportional to its surface area .Radius originally is 3 mm and 1 hour later has been reduced to 2 mm, find an expression for the radius of the rain drop at any time.

A right circular cone with radius R and height H contains a liquid which evaporates at a rate proportional to its surface area in contact with air (proportionality constant k is positive). Suppose that r(t) is the radius of the liquid cone at time t. The time after which the cone is empty is

The surface area of a spherical balloon being inflated, changes at a rate proportional to time t . If initially its radius is 1 unit and after 3 secons it is 2 units, find the radius after t seconds.

When liquid medicine of density rho is to be put in the eye, it is done with the help of a dropper. As the bylb on the top of the dropper is pressed. A drop frons at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy, To determine the size. We calculate the net vertical force due to the surface tension T when the radius of the drop is R. when this force become smaller than the weight of the drop the drop gets detached from the dropper. If the radius of the opening of the dropper is r, the vertical force due to the surface tension on the drop of radius R (assuming rlt ltR) is

When liquid medicine of density rho is to be put in the eye, it is done with the help of a dropper. As the bylb on the top of the dropper is pressed. A drop frons at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy, To determine the size. We calculate the net vertical force due to the surface tension T when the radius of the drop is R. when this force become smaller than the weight of the drop the drop gets detached from the dropper. After the drop detaches, its surface energy is

When liquid medicine of density rho is to be put in the eye, it is done with the help of a dropper. As the bylb on the top of the dropper is pressed. A drop frons at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy, To determine the size. We calculate the net vertical force due to the surface tension T when the radius of the drop is R. when this force become smaller than the weight of the drop the drop gets detached from the dropper. If r=5xx10^(-4)m,rho=10^(3) kg m^(-3), g=10ms^(-2), T=0.11Nm^(-1), The radius of the drop when it detaches from the dropper is approximately,