The distance between the middle point of `B C` and the foot of the perpendicular from `A` is:

If a=9,b=4a n dc=8 then find the distance between the middle point of BC and the foot of the perpendicular form Adot

If the coordinates of the points A,B,C be (-1,5),(0,0) and (2,2) respectively, and D be the middle point of BC, then the equation of the perpendicular drawn from B to the line AD is

Let A B C be a triangle with A B=A Cdot If D is the midpoint of B C ,E is the foot of the perpendicular drawn from D to A C ,a n dF is the midpoint of D E , then prove that A F is perpendicular to B Edot

Find the distance between the points (a,b) and (-b,a)

Find distance between the points A (a,b) and B( - b,a)

If the perpendicular distance of a point P from the X-axis is 5 units and the foot of the perpendicular lies on the negative direction of X-axis then the point P has

P is a point on either of the two lines y - sqrt3|x|=2 at a distance 5 units from their point of intersection The coordinates of the foot of the perpendicular from P on the bisector of the angle between them are

Write the coordinates of the foot of the perpendicular from the point (1,2,3) on y-axis.

A is a point on either of two lines y+sqrt(3)|x|=2 at a distance of 4sqrt(3) units from their point of intersection. The coordinates of the foot of perpendicular from A on the bisector of the angle between them are (a) (-2/(sqrt(3)),2) (b) (0,0) (c) (2/(sqrt(3)),2) (d) (0,4)

A plane passes through a fixed point (a ,b ,c)dot Show that the locus of the foot of the perpendicular to it from the origin is the sphere x^2+y^2+z^2-a x-b y-c z=0.