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From the top of a building 60m high the angles of depression of the top and the bottom of a tower are observed to be `30o` and `60o` . Find the height of the tower.

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`In /_ ABC`
`tan60= 60/x`
`tan30=(60-h)/x`
Hence, `tan60/tan30=60/(60-h)` `3=60/(60-h)`
`h=40`
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