The sum of 100 terms of the series `. 9+. 09+. 009` ..... will be
(a) `1-(1/1)^(100)`
(b) `1+(1/1)^(106)`
(c) `1-(1/1)^(106)`
(d) `1+(1/1)^(100)`

The sum of the n terms of the series 1+(1+3)+(1+3+5)+... is

The sum of 10 terms of the series 1+2(1.1)+3(1.1)^(2)+4(1.1)^(3)+…. is

[{(-1/3)^2}^(-2)]^(-1) = (a) 1/(81) (b) 1/9 (c) -1/(81) (d) -1/9

Sum to n terms of the series :1 + 2 (1 + (1)/(n)) + 3 (1 + (1)/(n )) ^(2) + ………

The sum of n terms of the series 5/1.2.1/3+7/2.3.1/3^2+9/3.4.1/3^3+11/4.5.1/3^4+.. is (A) 1+1/2^(n-1).1/3^n (B) 1+1/(n+1).1/3^n (C) 1-1/(n+1).1/3^n (D) 1+1/2n-1.1/3^n

Find the sum of first 100 terms of the series whose general term is given by a_k=(k^2+1)k !

Find the sum of firs 100 terms of the series whose general term is given by T_(r)=(r^(2)+1)r! .

Write the sum of 20 terms of the series: 1+1/2(1+2)+1/3(1+2+3)+

The sum to 100 terms of the series 1.2.3. + 2.3.4. + 3.4.5. + …+ n(n + 1) (n+2) + …. is integral multiple of

The sum of the series 2/3+8/9+(26)/(27)+(80)/(81)+ to n terms is (a) n-1/2(3^(-n)-1) (b) n-1/2(1-3^(-n)) (c) n+1/2(3^n-1) (d) n-1/2(3^n-1)