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There are 4 urns. The first urn contains...

There are 4 urns. The first urn contains 1 white and 1 black ball, the second um contains 2 white and 3 black balls, the third urn contains 3 white and 5 black balls & the fourth urn contains 4 white & 7 black balls. The selection of each um is not equally likely. The probability of selecting `i^(t h)urn` is `(i^2+1)/(34)(i=1,2,3,4)dot` If we randomly select one of the urns & draw a ball, then the probability of ball being white is: `(569)/(1496)` (b) `(27)/(56)` (c) `8/(73)` (d) None of these

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There are 4 urns. The first urn contains 1 white and 1 black ball, the second um contains 2 white and 3 black balls, the third urn contains 3 white and 5 black balls & the fourth urn contains 4 white & 7 black balls. The selection of each um is not equally likely. The probability of selecting i^(t h)u m is (i^2+1)/(34)(i=1,2,3,4)dot If we randomly select one of the urns & draw a ball, then the probability of ball being white is: (a) (569)/(1496) (b) (27)/(56) (c) 8/(73) (d) None of these

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