The continued product `2.6.10.14…..`(`n` times) in equal to

Find the product 7/18xx9/14

Find the products : 6.83 xx10

The solubility of AgCI(s) with solubility product 1.6 xx 10^(-10) in 0.1 M NaCl solution would be :

Find the product : 10.007 xx 11.1 xx 2

The solubility product of three sparingly soluble salts are given below: {:("No","Formula","Solubility product"),(1,PQ,4.0 xx 10^(-20),(2,PQ_(2),3.2 xx 10^(-14)),(3,PQ_(3), 2.7 xx 10^(-35)):} The correct order of decreasing molar solubility is

The ionic product of water is 0.11 xx 10 ^(-14) at 273 K. 1.0 xx 10 ^(-14) at 298 K and 5.1 xx 10 ^(-14) at 373 K Deduce from this data whether the ionisation of water to hydrogen and hydrooxide ions is exothermic or endothermic.

Taking the mass of earth equal to 6 xx 10^(24) kg and its radius equal to 6.4 xx 10^6 m, calculate the value of acceleration due to gravity at a height of 2000 km above the earth surface. Take G = 6.7xx10^(-11) N m^(2) kg^(-2)

When a coin is tossed n times, if the probability for getting 6 heads is equal to the probability of getting 8 heads, then the value of n is

If P_(n) = cos^(n) theta + sin^(n) theta 6P_(10) -15P_(8) + 10P_(6) is equal to

What will be solubility of A_(2)X_(3) if its solubility product (K_(sp)) is equal to 1.08 xx 10^(-23) ?