If `m^2-n^2= 7`, where `m, n epsilon Z`, then number of ordered pairs (m,n) is

The natural numbers ware not sufficient to deal with various equations that mathematicians encountered so some new sets of numbers were defined Ehole numbers (W) = {0,1,2,3,4,……….} Integers (Z or I) = (……, -3,-2,-1,1,0,2,3,4,……} Even integers :- Intigers divisible by 2, they are expressed as 2n n in Z. odd Integers :- Integers not divisible by 2, they are expressed as 2n+1or 2n-1,ninZ. If m^(2)-n^(2)=7, where m, n in Z, then number of ordered pairs (m,n) is

A matrix of order mxxn contains 7 elements, then how many different order pairs (m,n) can take ?

If A.M. and G.M. between two numbers is in the ratio m : n then prove that the numbers are in the ratio (m+sqrt(m^2-n^2)):(m-sqrt(m^2-n^2))dot

If A.M. and G.M. between two numbers is in the ratio m : n then prove that the numbers are in the ratio (m+sqrt(m^2-n^2)):(m-sqrt(m^2-n^2))dot

If A.M. and G.M. between two numbers is in the ratio m : n then prove that the numbers are in the ratio (m+sqrt(m^2-n^2)):(m-sqrt(m^2-n^2))

A square matrix M of order 3 satisfies M^(2)=I-M , where I is an identity matrix of order 3. If M^(n)=5I-8M , then n is equal to _______.

If two positive integers m and n are expressible in the form m=p q^3 and n=p^3q^2 , where p ,\ q are prime numbers, then HCF (m ,\ n)=

If two positive integers m and n are expressible in the form m=p q^3 and n=p^3q^2 , where p ,\ q are prime numbers, then HCF (m ,\ n)=

Find the number of ordered pairs (m,n)epsilon {1,2,…..20} such that 3^(m)+7^(n) is divisible by 10.

If a, b, c in N , the probability that a^(2)+b^(2)+c^(2) is divisible by 7 is (m)/(n) where m, n are relatively prime natural numbers, then m + n is equal to :