The function `f:[-1//2,\ 1//2]->[-pi//2,pi//2\ ]` defined by `f(x)=s in^(-1)(3x-4x^3)` is (a) bijection (b) injection but not a surjection (c) surjection but not an injection (d) neither an injection nor a surjection

The function f:[-1//2,\ 1//2]->[-pi//2,pi//2\ ] defined by f(x)=sin^(-1)(3x-4x^3) is (a) bijection (b) injection but not a surjection (c) surjection but not an injection (d) neither an injection nor a surjection

Let A{x :-1lt=xlt=1}a n df: Avec such that f(x)=x|x|, then f is (a) bijection (b) injective but not surjective (c)Surjective but not injective (d) neither injective nor surjective

Let A}x :-1lt=xlt=1}a n df: Avec A such that f(x)=x|x|, then f is (a) bijection (b) injective but not surjective Surjective but not injective (d) neither injective nor surjective

The function f: R->R , f(x)=x^2 is (a) injective but not surjective (b) surjective but not injective (c) injective as well as surjective (d) neither injective nor surjective

Let f : R->R be a function defined by f(x)=(e^(|x|)-e^(-x))/(e^x+e^(-x)) then --(1) f is bijection (2) f is an injection only (3) f is a surjection (4) f is neither injection nor a surjection

Show that f: R->R defined by f(x)=(x-1)(x-2)(x-3) is surjective but not injective.

Let f:[-oo,0)->(1,oo) be defined as f(x)=(1+sqrt(-x))-(sqrt(-x)-x) then f(x) is (A) injective but not surjective (B) injective as well as surjective (C) neither injective nor surjective (D) surjective nut not injective

Let R be the set of real numbers. If f:R->R is a function defined by f(x)=x^2, then f is injective but not surjective surjective but not injective bijective none of these (a) injective but not surjective (b) surjective but not injective (c) bijective (d) non of these

Classify f: N->N given by f(x)=x^2 as injection, surjection or bijection.

Classify f: Z->Z given by f(x)=x^2 as injection, surjection or bijection.