one vertex of the triangle of maximum area that can be inscribed in the curve `|z-2i|=2` is `2+2i,` then remaining vertices are

If one vertex of the triangle having maximum area that can be inscribed in the circle |z-i|=5i s3-3i , then find the other vertices of the triangle.

Show that the triangle of maximum area that can be inscribed in a given circle is an equilateral triangle.

Show that the triangle of maximum area that can be inscribed in a given circle is an equilateral triangle.

Show that the isosceles triangle of maximum area that can be inscribed in a given circle is an equilateral triangle .

The dimension of the rectangle of maximum area that can be inscribed in the ellipse (x//4)^(2) +(y//3)^(2) =1 are

A rectangle of maximum area is inscribed in the circle |z-3-4i|=1. If one vertex of the rectangle is 4+4i , then another adjacent vertex of this rectangle can be a. 2+4i b. 3+5i c. 3+3i d. 3-3i

Find the area of the greatest isosceles triangle that can be inscribed in the ellipse ((x^2)/(a^2))+((y^2)/(b^2))=1 having its vertex coincident with one extremity of the major axis.

Two vertices of a triangle are A(3,4,2) and B(1,3,2). The medians of the triangle intersect at (2,4,3). Find the remaining vertex C of the triangle.

The eccentric angles of the vertices of a triangle inscribed in the ellipse x^2/a^2 + y^2/b^2 =1 are alpha, beta, gamma , then for the area of this triangle to be greatest, the angle subtended by the two consecutive vertices of the triangle at the centre of the ellipse in degree measure is...

An isosceles triangle of vertical angle 2theta is inscribed in a circle of radius a . Show that the area of the triangle is maximum when theta=pi/6 .