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The distance of the point (1, 2, 3) from...

The distance of the point (1, 2, 3) from the plane `x+y-z=5` measured along the straight line `x=y=z` is `5sqrt(3)` (2) `10sqrt(3)` (3) `3sqrt(10)` `3sqrt(5)` (5) `2sqrt(5)`

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The distance of the point (1,-5,""9) from the plane x-y+z=5 measured along the line x=y=z is : (1) 3sqrt(10) (2) 10sqrt(3) (3) (10)/(sqrt(3)) (4) (20)/3

Find the distance of the point (2, 3, 4) from the plane 3x + 2y + 2z + 5= 0 measured parallel to the line (x+3)/3=(y-2)/6=z/2 .

If the image of the point P(1,-2,3) in the plane, 2x+3y-4z+22=0 measured parallel to the line, x/1=y/4=z/5 is Q , then P Q is equal to : sqrt(42) (2) 6sqrt(5) (3) 3sqrt(5) (4) 3sqrt(42)

The distance of point (-1, -5, -10) from the plane 10 x+2y-z=0 measured parallel to the line x/3=(y-1)/4=(z+1)/(12) is: (A) 10sqrt(2) (B) 5 (C) 11 (D) none of these

Find the distance of the point (2, 3, 4) from the line (x+3)/3=(y-2)/6=z/2 measured parallel to the plane 3x + 2y + 2z - 5= 0 .

The graph of straight line y = sqrt(3)x + 2sqrt(3) is :

The radius of the circle touching the straight lines x-2y-1=0 and 3x-6y+7=0 is (A) 1/sqrt(2) (B) sqrt(5)/3 (C) sqrt(3) (D) sqrt(5)

Find sqrt(2+3sqrt(-5)) + sqrt(2-3sqrt(-5))

Simplify: 2/(sqrt(5)+\ sqrt(3))+1/(sqrt(3)+\ sqrt(2))-3/(sqrt(5)+\ sqrt(2))

If 5-sqrt(3)=x+y sqrt(3) then (x,y) is

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